Define a structure of employee having data

Define a structure of employee having data
members name, address, age and salary. Take
data for n employee in an array dynamically
and find the average salary.

#include <stdio.h>
#include <stdlib.h>

typedef struct{
    char name[30];
    int id;
    double salary;
} Employee;
  float avg;
  int sum,i;

int main()
{
    sum =avg= 0;
    //number of employees
    int n=2;

    //array to store structure values of all employees
    Employee employees[n];

    //Taking each employee detail as input
    printf("Enter %d Employee Details \n \n",n);
    for(int i=0; i<n; i++){


        printf("Employee %d:- \n",i+1);

        //Name
        printf("Name: ");
        scanf("%[^\n]s",employees[i].name);

        //ID
        printf("Id: ");
        scanf("%d",&employees[i].id);

        //Salary
        printf("Salary: ");
        scanf("%lf",&employees[i].salary);

        //to consume extra '\n' input
        char ch = getchar();

        sum=sum+employees[i].salary;

        printf("\n");
    }

    //Displaying Employee details
    printf("-------------- All Employees Details ---------------\n");
    for(int i=0; i<n; i++){
        printf("Name \t: ");
        printf("%s \n",employees[i].name);

        printf("Id \t: ");
        printf("%d \n",employees[i].id);

        printf("Salary \t: ");
        printf("%.2lf \n",employees[i].salary);

         avg=(float)sum/2;

   printf("Average of array values is %.2f", avg);
        printf("\n");
    }




    return 0;
}